b^2+5b-15=9

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Solution for b^2+5b-15=9 equation:


Simplifying
b2 + 5b + -15 = 9

Reorder the terms:
-15 + 5b + b2 = 9

Solving
-15 + 5b + b2 = 9

Solving for variable 'b'.

Reorder the terms:
-15 + -9 + 5b + b2 = 9 + -9

Combine like terms: -15 + -9 = -24
-24 + 5b + b2 = 9 + -9

Combine like terms: 9 + -9 = 0
-24 + 5b + b2 = 0

Factor a trinomial.
(-8 + -1b)(3 + -1b) = 0

Subproblem 1

Set the factor '(-8 + -1b)' equal to zero and attempt to solve: Simplifying -8 + -1b = 0 Solving -8 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -1b = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -1b = 0 + 8 -1b = 0 + 8 Combine like terms: 0 + 8 = 8 -1b = 8 Divide each side by '-1'. b = -8 Simplifying b = -8

Subproblem 2

Set the factor '(3 + -1b)' equal to zero and attempt to solve: Simplifying 3 + -1b = 0 Solving 3 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -1b = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -1b = 0 + -3 -1b = 0 + -3 Combine like terms: 0 + -3 = -3 -1b = -3 Divide each side by '-1'. b = 3 Simplifying b = 3

Solution

b = {-8, 3}

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